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Oct 11, 2024
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34 changes: 34 additions & 0 deletions find-minimum-in-rotated-sorted-array/jdalma.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,34 @@
class `find-minimum-in-rotated-sorted-array` {

/**
* TC: O(log N), SC: O(1)
*/
fun findMin(nums: IntArray): Int {
var (low, high) = 0 to nums.size - 1
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var (low, high) = 0 to nums.size - 1
kotlin에서 pair를 만드는 표현이 참 특이하네요 ㅎㅎ


while (low + 1 < high) {
val mid = (low + high) / 2
if (nums[mid - 1] > nums[mid]) {
return nums[mid]
}
if (nums[mid] < nums[high]) {
high = mid
}
else {
low = mid
}
}
Comment on lines +9 to +20
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이진탐색 로직이 깔끔하고 좋습니다 ㅎㅎ
저도 현준님 풀이에 영감을 얻어서 제 풀이를 좀 더 다듬을 수 있었습니다 :)
https://github.com/DaleStudy/leetcode-study/pull/520/files#diff-d02da092874d1658e6fb39bb2d7221b29a6fe6804b26e2c460bdd0e2243dd373

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전에 obzva님이 전달해주신 이진 검색 정리 게시글을 본게 도움 많이 되었습니다! 감사합니다 ㅎㅎ


return min(nums[low], nums[high])
}

@Test
fun `입력받은 정수 배열의 최소 원소를 반환한다`() {
findMin(intArrayOf(4,5,6,7,0,1,2)) shouldBe 0
findMin(intArrayOf(2,3,0,1)) shouldBe 0
findMin(intArrayOf(2,3,1)) shouldBe 1
findMin(intArrayOf(2,1,3)) shouldBe 1
findMin(intArrayOf(2,3,4,5,1)) shouldBe 1
findMin(intArrayOf(11,13,15,17)) shouldBe 11
}
}
45 changes: 45 additions & 0 deletions linked-list-cycle/jdalma.kt
Original file line number Diff line number Diff line change
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package leetcode_study

import io.kotest.matchers.shouldBe
import org.junit.jupiter.api.Test

class `linked-list-cycle` {

data class ListNode(var `val`: Int) {
var next: ListNode? = null
}

/**
* TC: O(n), SC: O(1)
*/
fun hasCycle(head: ListNode?): Boolean {
if (head == null) return false

var slow = head
var fast = head

while (fast?.next != null) {
slow = slow?.next
fast = fast.next?.next

if (slow == fast) return true
}

return false
}

@Test
fun `입력받은 노드에 사이클이 존재한다면 참을 반환한다`() {
val three = ListNode(3)
val two = ListNode(2)
val zero = ListNode(0)
val four = ListNode(4)

three.next = two
two.next = zero
zero.next = four
four.next = two

hasCycle(three) shouldBe true
}
}
73 changes: 73 additions & 0 deletions merge-intervals/jdalma.kt
Original file line number Diff line number Diff line change
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package leetcode_study

import io.kotest.matchers.shouldBe
import org.junit.jupiter.api.Test
import kotlin.math.max

class `merge-intervals` {

data class CustomRange(
var start: Int,
var end: Int
) {
fun isMergePossible(s: Int) = s <= this.end
}

/**
* TC: O(n log n), SC: O(n)
*/
fun merge(intervals: Array<IntArray>): Array<IntArray> {
val sorted = intervals.sortedWith { i1, i2 -> i1[0].compareTo(i2[0]) }
val result = mutableListOf<CustomRange>()

var tmp = sorted.first().let {
CustomRange(it[0], it[1])
}
result.add(tmp)
for (interval in sorted) {
if (tmp.isMergePossible(interval[0])) {
tmp.end = max(interval[1], tmp.end)
} else {
tmp = CustomRange(interval[0], interval[1])
result.add(tmp)
}
}

return result.map { intArrayOf(it.start, it.end) }
.toTypedArray()
}

@Test
fun `2차원 배열의 원소인 start와 end만큼 병합한 결과를 반환한다`() {
merge(
arrayOf(
intArrayOf(2,6),
intArrayOf(8,10),
intArrayOf(15,18),
intArrayOf(1,3)
)
) shouldBe arrayOf(
intArrayOf(1,6),
intArrayOf(8,10),
intArrayOf(15,18)
)

merge(
arrayOf(
intArrayOf(1,4),
intArrayOf(0,4)
)
) shouldBe arrayOf(
intArrayOf(0,4)
)

merge(
arrayOf(
intArrayOf(1,4),
intArrayOf(0,1)
)
) shouldBe arrayOf(
intArrayOf(0,4)
)
}
}
75 changes: 75 additions & 0 deletions pacific-atlantic-water-flow/jdalma.kt
Original file line number Diff line number Diff line change
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package leetcode_study

import io.kotest.matchers.shouldBe
import org.junit.jupiter.api.Test

class `pacific-atlantic-water-flow` {

private val dirs = listOf(
intArrayOf(0, 1),
intArrayOf(0, -1),
intArrayOf(1, 0),
intArrayOf(-1, 0)
)

/**
* TC: O(n * m), SC: O(n * m)
*/
fun pacificAtlantic(heights: Array<IntArray>): List<List<Int>> {
val (row, col) = heights.size to heights.first().size
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코틀린에 문법 관련 단순 질문입니다 :)
이렇게 튜플 형태로 변수를 초기화하면 '한 줄에 작성하기'외에 혹시 다른 장점이 있나요?

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제가 알기로는 가독성 외에는 딱히 다른 장점은 없는걸로 알고있습니다 ㅎㅎ

val pacific = Array(row) { BooleanArray(col) }
val atlantic = Array(row) { BooleanArray(col) }

for (index in 0 until row) {
dfs(heights, pacific, Int.MIN_VALUE, index, 0)
dfs(heights, atlantic, Int.MIN_VALUE, index, col - 1)
}

for (index in 0 until col) {
dfs(heights, pacific, Int.MIN_VALUE, 0, index)
dfs(heights, atlantic, Int.MIN_VALUE, row - 1, index)
}

val result = mutableListOf<List<Int>>()
for (i in 0 until row) {
for (j in 0 until col) {
if (pacific[i][j] && atlantic[i][j]) {
result.add(listOf(i, j))
}
}
}
return result
}

private fun dfs(heights: Array<IntArray>, visited: Array<BooleanArray>, height: Int, r: Int, c: Int) {
val (row, col) = heights.size to heights.first().size
if (r < 0 || r >= row || c < 0 || c >= col || visited[r][c] || heights[r][c] < height)
return

visited[r][c] = true
for (dir in dirs) {
dfs(heights, visited, heights[r][c], r + dir[0], c + dir[1])
}
}

@Test
fun `태평양과 대서양에 모두 흐를 수 있는 셀의 위치를 반환하라`() {
pacificAtlantic(
arrayOf(
intArrayOf(1,2,2,3,5),
intArrayOf(3,2,3,4,4),
intArrayOf(2,4,5,3,1),
intArrayOf(6,7,1,4,5),
intArrayOf(5,1,1,2,4)
)
) shouldBe arrayOf(
intArrayOf(0,4),
intArrayOf(1,3),
intArrayOf(1,4),
intArrayOf(2,2),
intArrayOf(3,0),
intArrayOf(3,1),
intArrayOf(4,0)
)
}
}