[Wan] Week 1 #683
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[Wan] Week 1 #683
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TonyKim9401
approved these changes
Dec 13, 2024
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| const set = new Set<number>(); | ||
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| for (let i = 0; i < nums.length; i++) { | ||
| if (set.has(nums[i])) { | ||
| return true; | ||
| } | ||
| set.add(nums[i]); | ||
| } | ||
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| return false; |
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아래와 같이 한줄로 풀이하는 방법도 있을것 같습니다 :)
new Set(nums).size !== nums.length;
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| const chars = s.replace(/[^a-z0-9]/gi, "").toLowerCase(); | ||
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| return chars === [...chars].reverse().join(""); |
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정규식과 리스트 관련 함수를 잘 활용하신것 같아요 :)
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@taewanseoul 님, 프로젝트의 주차 지정이 안 되어 있이서 제가 대신 해드렸습니다. 스터디 진행 현황 파악에 중요한 부분이오니 다음 PR부터는 누락되지 않도록 주의 부탁드립니다. 관련해서 답안 제출 가이드도 참고하세요.
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확인 감사합니다! 주의하겠습니다. |
yeeZinu
approved these changes
Dec 15, 2024
| */ | ||
| function longestConsecutive(nums: number[]): number { | ||
| const set = new Set(nums); | ||
| const sorted = [...set].sort((a, b) => a - b); |
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set을 사용하신김에 has로 원하는 수가 set안에 있는지 확인하는 방법을 사용할 수도 있을것같습니다!
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답안 제출 문제
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