Skip to content

[jj7779607] Week4 #827

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 2 commits into from
Jan 5, 2025
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
29 changes: 29 additions & 0 deletions merge-two-sorted-lists/limlimjo.js
Copy link
Contributor

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

리뷰가 너무 늦어 죄송합니다 ^ㅠ 재귀로 링크드 리스트를 병합하는 방법을 잘 배우고 갑니다. 이번 주도 수고하셨습니다!

Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} list1
* @param {ListNode} list2
* @return {ListNode}
*/
var mergeTwoLists = function (list1, list2) {
// 리스트가 비었을 때 다른 리스트 반환
if (list1 === null) return list2;
if (list2 === null) return list1;

// 작은 값 가진 노드 선택하고 재귀호출
if (list1.val <= list2.val) {
list1.next = mergeTwoLists(list1.next, list2);
return list1;
} else {
list2.next = mergeTwoLists(list1, list2.next);
return list2;
}
};

// 시간 복잡도: O(n1+n2)
// 공간 복잡도: O(1)
17 changes: 17 additions & 0 deletions missing-number/limlimjo.js
Copy link
Contributor

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

정렬 후 인덱스 비교하는 건 좋은 아이디어인 것 같습니다.

공간복잡도는 O(1)으로 유지하고 시간복잡도는 O(n) 으로 줄이기 위해, 수학적 합 공식을 활용해봐도 좋을 것 같아요!

Copy link
Contributor Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

시간복잡도를 줄이기 위해 수학적 합 공식 한번 활용해봐야겠네요! 감사합니다!

Original file line number Diff line number Diff line change
@@ -0,0 +1,17 @@
/**
* @param {number[]} nums
* @return {number}
*/
var missingNumber = function (nums) {
// 1. nums 정렬
nums.sort((a, b) => a - b);
// 2. for문 돌며 빠진 숫자 찾기
for (let i = 0; i <= nums.length; i++) {
if (nums[i] !== i) {
return i;
}
}
};

// 시간 복잡도: O(nlogn)
// 공간 복잡도: O(1)
Loading