提交作业0926-hard -4 #12
提交作业0926-hard -4 #12
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| let start = i, end = len1 - 1; | ||
| if (j < len2){ | ||
| start = j, end = len2 - 1; | ||
| while (start <= end){ | ||
| arr.push(nums2[start++]); | ||
| } | ||
| } else{ | ||
| while (start <= end){ | ||
| arr.push(nums1[start++]); | ||
| } | ||
| } |
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这一段写的太复杂了，没必要再弄两个变量，直接两个循环就可以。
while (i < ken1){}
while (j < len2){}
由于这两个只会有一个被满足，所以不会有多余的运算。
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这一段写的太复杂了，没必要再弄两个变量，直接两个循环就可以。
while (i < ken1){}while (j < len2){}
由于这两个只会有一个被满足，所以不会有多余的运算。
好的黄总 我想一下
| var findMedianSortedArrays = function (nums1, nums2){ | ||
| let len1 = nums1.length; | ||
| let len2 = nums2.length; | ||
| let sum = len1 + len2; |
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这个变量命名不是很喜欢，可以用 length, length_sum，为啥要单用 sum...
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这个变量命名不是很喜欢，可以用 length, length_sum，为啥要单用 sum...
老子乐意
| //排序 | ||
| var findMedianSortedArrays = function (nums1, nums2){ | ||
| let nums = nums1.concat(nums2).sort((a,b)=>{return a-b}); | ||
| nums1 = null;nums2 = null; |
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这里为啥要把 nums1 和 nums2 置空，有什么必要么?
没啥必要 就是想着手动释放内存
| * @param {number} numRows | ||
| * @return {string} | ||
| */ | ||
| var convert = function (s, numRows){ |
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写一下思路
好的 黄总 我写下思路
| } | ||
| return res.join("") | ||
| }; | ||
| var convert1 = function convert(s, numRows){ |
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这个也写一下思路，不然代码太难懂了
好的黄总
| r = i===0?0:i % (rows * 2); | ||
| count=i===0?0:Math.floor(i / (rows * 2)); |
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这个是不是用一个 if 更好一些，可以少一次判断，且代码逻辑更加清晰
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这个是不是用一个 if 更好一些，可以少一次判断，且代码逻辑更加清晰
好的黄总
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