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The Javascript object arguments should work function-scoped oriented. Here follows an example:

function g()
{
	function f()
        {
		for(var i = 0; i < arguments.length; i++)
                {
			console.log(arguments[i]);
		}
	}
        
        //Calling f
        f();
}

//Outputs: undefined
g(1,2,3,4,5);

By analysing the listing above, it should be said that arguments in the nested function f works only for this function. This should be the reason why g(1,2,3,4,5) outputs undefined . To output the arguments (1,2,3,4,5) with the object arguments the code could look like as follows:

function g()
{
    //Object "arguments" here belongs to the function g()
    for(var i = 0; i < arguments.length; i++)
    {
    	console.log(arguments[i]);
    }

    function f()
    {
        //Object arguments here belongs to the function f()
	for(var i = 0; i < arguments.length; i++)
        {
		console.log(arguments[i]);
	}
    }

    f();

}

//Outputs: 1,2,3,4 and 5
g(1,2,3,4,5);

📕 It should be possible to give the arguments of g to the function f by saving g's object arguments to a variable as the following example should show:

function g()
{
	var parameters = arguments;

	function f()
        {
		for(var i = 0; i < parameters.length; i++)
                {
			console.log(parameters[i]);
		}
	}

	f();
}

//Outputs: 1,2,3,4 and 5
g(1,2,3,4,5);

Again, the last listing should work, because Javascript should be function-scoped.

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