Skip to content

Add maximum-product-subarray solution #3

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 1 commit into from
Sep 7, 2024
Merged
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
18 changes: 18 additions & 0 deletions maximum-product-subarray/joon.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,18 @@
from typing import List


class Solution:
# Time: O(n)
# Space: O(n)
def maxProduct(self, nums: List[int]) -> int:
maxProducts = [nums[0]]
minProducts = [nums[0]]
# Store all max/minProducts[i]: the max/min product of all subarrays that have nums[i] as the last element.
# Time: O(n)
# Space: O(n)
for num in nums[1:]:
newMaxProduct = max(maxProducts[-1] * num, minProducts[-1] * num, num)
newMinProduct = min(maxProducts[-1] * num, minProducts[-1] * num, num)
maxProducts.append(newMaxProduct)
minProducts.append(newMinProduct)
return max(maxProducts)