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Checkes if a given year is leap year or not #29

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Oct 9, 2021
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Checkes if a given year is leap year or not #29

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21 changes: 21 additions & 0 deletions Programs/LeapYear.py
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# Checkes if a given year is leap year or not

# To determine whether a year is a leap year, follow these steps:
# Step 1: If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5
# Step 2: If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4
# Step 3: If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5
# Step 4: The year is a leap year (it has 366 days)
# Step 5: The year is not a leap year (it has 365 days)

year = int(input("Enter a year: "))

if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))