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is the mse layer really divide by the number of size ? #2246
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In the mse_cost in Layers.py. We see the description is$\frac{1}{N}\sum_{i=1}^N(t _i- y_i)^2$ , I think N is the size of each item
However, when I check the implementation it calls sumofsquarediff, which does not do a normalization of layer size N. I think it is a wrong description of the mse_cost layer ?
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