Refactor: Use counter for group macros

[BrettMayson]

Personally I prefer this as you don't need to declare a macro for each, don't need to worry about calling them in the correct order, although you do need to call __COUNTER_RESET__ at the start

Depends on #107 because I was using a dev build of HEMTT that doesn't like the current master. Looks like current HEMTT also doesn't like __COUNTER_RESET__ for some reason.

(This PR will look better once #107 is on master)

[BrettMayson]

@Mike-MF Are you interested in this? Do I update it?

[Mike-MF]

eh, It's a lot of work I'd just close it

[BrettMayson]

I mean, not really. just a preference thing

[jonpas]

I like it, it simplifies things.

[Mike-MF]

Feel free, might be placebo but using ranks more "correctly" seems to actually affect how quickly group leaders change with less downtime on AI actually doing stuff. Added it into the macro below how it is currently, hopefully it's right as I'm still mostly asleep.

// Group Macros
#define GROUP_UNIT(UNIT,SIDE) __GROUP_UNIT(__COUNTER__, UNIT, SIDE)

#define __GROUP_UNIT(COUNTER, UNIT, SIDE) \
    class unit##COUNTER { \
        vehicle = #UNIT; \
        side = SIDE; \
        #if COUNTER == 0 \
        rank = "SERGEANT"; \
        #else \
        #if COUNTER == 2 \
        rank = "SERGEANT"; \
        #else \
        #if COUNTER == 3 \
        rank = "CORPORAL"; \
        #else \
        #if COUNTER == 5 \
        rank = "SERGEANT"; \
        #else \
        #if COUNTER == 6 \
        rank = "CORPORAL"; \
        #else \
        rank = "PRIVATE"; \
        #endif \
        #endif \
        #endif \
        #endif \
        #endif \
        position[] = { \
            QUOTE(5 * floor ((COUNTER + 1) / 2) * (-1 ^ (COUNTER + 1))), \
            QUOTE(-5 * floor ((COUNTER + 1) / 2)), \
            0 \
        }; \
    }