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We should be able to concatenate two streams one by one, though at least the first argument stream should be a Finite stream, and the resulted stream type depends on the second argument type.
We may use range operator overload for this:
val concatenation = finiteStream .. anotherStream
The sample type can be any but must be the same for both streams.
The text was updated successfully, but these errors were encountered:
We should be able to concatenate two streams one by one, though at least the first argument stream should be a Finite stream, and the resulted stream type depends on the second argument type.
We may use range operator overload for this:
The sample type can be any but must be the same for both streams.
The text was updated successfully, but these errors were encountered: