Linux 纯终端模式下如何运行?

[mlxzlas]

一直都是在一个局域网中部署一台 goagent/xxnet 的服务器, 给其他所有的设备做代理,这样非常方便,
没有 x 的情况下运行 xxnet
在 2.0 之前的版本, 用 non_tray.py 替换 gtk_tray.py 就可以了
现在替换之后还是会报如下问题

Traceback (most recent call last):
File "launcher/start.py", line 23, in
if X_is_running():
File "launcher/start.py", line 19, in X_is_running
p = Popen(["xset", "-q"], stdout=PIPE, stderr=PIPE)
File "/usr/lib/python2.7/subprocess.py", line 679, in init
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1259, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory

---

[xxnet]

跟替换没有关系, 是找不到xset， xset是Xwindows的一个工具， 没有装xwindows，就没有这个工具，这里的自动检测好要再完善。
你可以先看看start.py，能不能直接注释掉检测，直接进入non_tray的分支

后面再修复这个问题

2015-07-24 9:35 GMT+08:00 Will Winters notifications@github.com:

一直都是在一个局域网中部署一台 goagent/xxnet 的服务器, 给其他所有的设备做代理,这样非常方便,
没有 x 的情况下运行 xxnet
在 2.0 之前的版本, 用 non_tray.py 替换 gtk_tray.py 就可以了
现在替换之后还是会报如下问题

Traceback (most recent call last):
File "launcher/start.py", line 23, in
if X_is_running():
File "launcher/start.py", line 19, in X_is_running
p = Popen(["xset", "-q"], stdout=PIPE, stderr=PIPE)
File "/usr/lib/python2.7/subprocess.py", line 679, in init
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1259, in _execute_child
raise child_exception

OSError: [Errno 2] No such file or directory

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#715.

[mlxzlas]

注释掉了检测,直接用 non_tray 分支可以执行了,但是又遇到新的问题

进入后居然直接打开了一个 w3m 浏览器, 如果使用其代理的话,就会出现如下错误

Traceback (most recent call last):
File "/usr/lib/python2.7/SocketServer.py", line 593, in process_request_thread
self.finish_request(request, client_address)
File "/path/to/xxnet/launcher/web_control.py", line 48, in finish_request
self.RequestHandlerClass(request, client_address, self)
File "/usr/lib/python2.7/SocketServer.py", line 649, in init
self.handle()
File "/usr/lib/python2.7/BaseHTTPServer.py", line 340, in handle
self.handle_one_request()
File "/usr/lib/python2.7/BaseHTTPServer.py", line 328, in handle_one_request
method()
File "/path/to/xxnet/launcher/web_control.py", line 143, in do_GET
controler = module_init.proc_handler[module]["imp"].local.web_control.ControlHandler(self.client_address, self.headers, self.command, path, self.rfile, self.wfile)
KeyError: 'imp'

[xxnet]

试试注释掉下面两行，可以不弹出w3m浏览器。
if config.get(["modules", "launcher", "popup_webui"], 1) == 1:
webbrowser.open("http://127.0.0.1:8085/")

你试试直接启动:
python gae_proxy/local/proxy.py 这样可以跳过launcher

2015-07-24 20:03 GMT+08:00 Will Winters notifications@github.com:

注释掉了检测,直接用 non_tray 分支可以执行了,但是又遇到新的问题

进入后居然直接打开了一个 w3m 浏览器, 如果使用其代理的话,就会出现如下错误

Traceback (most recent call last):
File "/usr/lib/python2.7/SocketServer.py", line 593, in
process_request_thread
self.finish_request(request, client_address)
File "/path/to/xxnet/launcher/web_control.py", line 48, in finish_request
self.RequestHandlerClass(request, client_address, self)
File "/usr/lib/python2.7/SocketServer.py", line 649, in init
self.handle()
File "/usr/lib/python2.7/BaseHTTPServer.py", line 340, in handle
self.handle_one_request()
File "/usr/lib/python2.7/BaseHTTPServer.py", line 328, in
handle_one_request
method()
File "/path/to/xxnet/launcher/web_control.py", line 143, in do_GET
controler =
module_init.proc_handler[module]["imp"].local.web_control.ControlHandler(self.client_address,
self.headers, self.command, path, self.rfile, self.wfile)
KeyError: 'imp'

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#715 (comment).