π₄S³≡ℤ/2 #715
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π₄S³≡ℤ/2 #715
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mortberg
requested changes
Feb 8, 2022
| @@ -4,13 +4,16 @@ This file contains a summary of what remains for π₄(S³) ≡ ℤ/2ℤ to be p | |||
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Actually I think the file should be reorganized a bit, maybe dropping the π₄S³ module and just stating the key results in sequence
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@mortberg So, fixed the stuff now. As discussed I left the summary file for you:-) |
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Congratulations! It's great to see a complete formalization come into reality! |
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Finally managed to clean this mess up a bit... This PR contains the final steps of the proof of π₄S³≡ℤ/2. More specifically:
Exact4). This construction was pretty useful for transporting between various exact sequences, so I think we should keep it. It captures a pretty common situation anyway.Cubical.Homotopy.Group.Pi4S3.BrunerieIso)Cubical.Homotopy.HopfInvariant.Brunerie.Cubical.Homotopy.Group.Pi4S3.Summary)