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搜索出JSONObject里面某个value对应的所有PATH #709

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baijian opened this issue Jul 4, 2016 · 4 comments
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搜索出JSONObject里面某个value对应的所有PATH #709

baijian opened this issue Jul 4, 2016 · 4 comments
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@baijian
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baijian commented Jul 4, 2016

一个JSONObject,递归遍历所有的叶子节点值,搜索出某个值对应的所有path返回,希望可以提供对应的方法直接使用.

@wenshao
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wenshao commented Jul 7, 2016

为什么有这个需求?怎样的一个使用场景?

@wenshao wenshao added this to the 1.2.14 milestone Jul 7, 2016
@baijian
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baijian commented Jul 7, 2016

类比的业务场景如下:

{
  "name": "test",
  "members": [
    {
       "name": "name1"
       "age": 12,
    },
    {
      "name": "name2",
      "age": 22,
    }
  ],
  "adminMembers" [
   {
       "name": "name3"
       "age": 12,
    },
    {
      "name": "name4",
      "age": 22,
    }
  ],
}

如上的一个json,我用这样的一个json来存储信息,一般情况下我知道path可以找出某个人的age,另外一种场景就是我现在知道一个人的name,想知道他的path,然后也就可以通过path知道这个人的信息以及其他信息了.

@wenshao
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wenshao commented Jul 12, 2016

已经实现,方法是

public class JSONPath {
    public static Map<String, Object> paths(Object javaObject);
}

看是否符合你的要求

@baijian
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baijian commented Jul 14, 2016

满足~

@baijian baijian closed this as completed Jul 14, 2016
asa1997 pushed a commit to Be-Secure/fastjson that referenced this issue Feb 8, 2023
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