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Using with two-factor authentication, not possible to disable 2FA #61
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Try changing you Apple ID password. It will erase all previous app-specific passwords, while keeping 2FA. This will allow you to sign in with your Apple ID and your new password. |
Any solution for this yet? Changing the password doesn't work, as AltStore still says that 2FA isn't allowed, but 2FA is mandatory for Apple. |
FAQ is not up to date. Download latest client from Riley's Twitter, than simply use your password, even if it has 2FA active. Or even a throw-away account, as it doesn't need to be the same account. I can confirm it works for me. |
So I can create a throwaway Apple ID for use with this server, it doesn’t have to be the same account I use on my iPhone? |
Exactly. Can be or not, doesn't make a difference.
Em seg, 23 de dez de 2019 às 22:03, elmstreetvictim <
notifications@github.com> escreveu:
FAQ is not up to date. Download latest client from Riley's Twitter, than
simply use your password, even if it has 2FA active. Or even a throw-away
account, as it doesn't need to be the same account. I can confirm it works
for me.
So I can create a throwaway Apple ID for use with this server, it doesn’t
have to be the same account I use on my iPhone?
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Also should be able to create an App-specific password via https://appleid.apple.com if you have 2FA setup. Then just use that specific password. |
This should be fixed on the latest versions of AltStore/Altserver. Closing this issue. |
I found a solution for this, which exploits the fact that a factor that has been generated for sign-in request A can be used for sign-in request B.
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Unfortunately Apple does not allow users to disable 2FA after a two-weeks period. I have activated 2FA a long ago and now that app-specific passwords are not allowed anymore, I am not able to use AltStore anymore.
Is there another possible workaround? Does the Apple account need to be the same Apple account used on the iPhone, or can it be a new Apple account, different from the one being used on the phone?
The error displayed is the same of the #57, though. Creating another issue because even though the error displayed is the same, I believe this is a different issue.
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