boolean indexing giving faulty results

[ZacDiggum]

Consider this:

a = af.constant(0., d0=3, d1=3)
a[1,1] = 1.

This one makes the whole second row into 2s:
a[a>0.] = 2.
While pavanky's trick gives the correct result:

cond = a>0
a = a*(1-cond)+cond*2.

Update: this also gives wrong results:
a[af.algorithm.where(a>0.)] = 2.

[pavanky]

@ZacDiggum This should be fixed in devel. Let me know if the problem still persists.