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Define __prepare__() in with_metaclass() #178
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Define `__prepare__()` in `with_metaclass()`'s temporary metaclass, and make sure that it passes the correct bases to the real metaclass's `__prepare__()`. The temporary metaclass previously didn't extend the `__prepare__()` method, which meant that if the real metaclass had a `__prepare__()`, it wouldn't get called correctly. This could lead to bugs in Python 3 code. The temporary metaclass's `__prepare__()` gets called with ```bases=(temporary_class,)```. Since there was no proxy in the middle, that was getting passed directly to the real metaclass's `__prepare__()`. But then, if the real class's `__prepare__()` method depended on the bases, the logic would be incorrect. This was a problem in projects that use `enum` / `enum34` and try to use `with_metaclass(EnumMeta)`. `enum34.EnumMeta` doesn't define `__prepare__()`, since it is a Python 2 backport. Python 3's `enum.EnumMeta` does define `__prepare__()`, but originally didn't depend at all on the bases. But starting in Python 3.6, `enum.EnumMeta.__prepare__()` will raise `TypeError` if the bases aren't valid for an enum subclass. Thus, a codebase that was successfully using `enum` / `enum34` and `with_metaclass(EnumMeta)` could break on Python 3.6.
benjaminp
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jmoldow
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Sep 18, 2017
Add a fallback for `six.raise_from`, which isn't available in six 1.4.0. It isn't available until six 1.9.0. We could also have raised the lower bound for the six requirement, but this is an easy way to allow clients to keep using their existing versions of six. Fix support for the latest version of six, 1.11.0. That release changed the temporary metaclass returned from `with_metaclass()`, such that it directly inherits from `type`, instead of inheriting from the target metaclass [1]. We depended on this detail, and the change caused .. code-block:: python TypeError('metaclass conflict: ...') to be raised when defining a class with `with_metaclass()`. We fix this by manually selecting the most derived metaclass, and including it in our temporary metaclass. Also, `__prepare__` is now defined on the temporary metaclass, in six 1.11.0 [2]. This allows us to skip our own definition of that method, when using six>=1.11.0. Fixes #228. Fixes #239. [1] <benjaminp/six#191> [2] <benjaminp/six#178>
jmoldow
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Sep 18, 2017
Add a fallback for `six.raise_from`, which isn't available in six 1.4.0. It isn't available until six 1.9.0. We could also have raised the lower bound for the six requirement, but this is an easy way to allow clients to keep using their existing versions of six. Fix support for the latest version of six, 1.11.0. That release changed the temporary metaclass returned from `with_metaclass()`, such that it directly inherits from `type`, instead of inheriting from the target metaclass [1]. We depended on this detail, and the change caused .. code-block:: python TypeError('metaclass conflict: ...') to be raised when defining a class with `with_metaclass()`. We fix this by manually selecting the most derived metaclass, and including it in our temporary metaclass. Also, `__prepare__` is now defined on the temporary metaclass, in six 1.11.0 [2]. This allows us to skip our own definition of that method, when using six>=1.11.0. Fixes #228. Fixes #239. [1] <benjaminp/six#191> [2] <benjaminp/six#178>
jmoldow
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to box/box-python-sdk
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Sep 18, 2017
Add a fallback for `six.raise_from`, which isn't available in six 1.4.0. It isn't available until six 1.9.0. We could also have raised the lower bound for the six requirement, but this is an easy way to allow clients to keep using their existing versions of six. Fix support for the latest version of six, 1.11.0. That release changed the temporary metaclass returned from `with_metaclass()`, such that it directly inherits from `type`, instead of inheriting from the target metaclass [1]. We depended on this detail, and the change caused .. code-block:: python TypeError('metaclass conflict: ...') to be raised when defining a class with `with_metaclass()`. We fix this by manually selecting the most derived metaclass, and including it in our temporary metaclass. Also, `__prepare__` is now defined on the temporary metaclass, in six 1.11.0 [2]. This allows us to skip our own definition of that method, when using six>=1.11.0. Fixes #228. Fixes #239. [1] <benjaminp/six#191> [2] <benjaminp/six#178>
jmoldow
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Sep 19, 2017
Update minimum required version of `six` to 1.9.0, so that `six.raise_from` can be safely used by all clients. Fix support for the latest version of six, 1.11.0. That release changed the temporary metaclass returned from `with_metaclass()`, such that it directly inherits from `type`, instead of inheriting from the target metaclass [1]. We depended on this detail, and the change caused .. code-block:: python TypeError('metaclass conflict: ...') to be raised when defining a class with `with_metaclass()`. We fix this by manually selecting the most derived metaclass, and including it in our temporary metaclass. Also, `__prepare__` is now defined on the temporary metaclass, in six 1.11.0 [2]. This allows us to skip our own definition of that method, when using six>=1.11.0. Fixes #228. Fixes #239. [1] <benjaminp/six#191> [2] <benjaminp/six#178>
jmoldow
added a commit
to box/box-python-sdk
that referenced
this pull request
Sep 19, 2017
Add a fallback for `six.raise_from`, which isn't available in six 1.4.0. It isn't available until six 1.9.0. We could also have raised the lower bound for the six requirement, but this is an easy way to allow clients to keep using their existing versions of six. Fix support for the latest version of six, 1.11.0. That release changed the temporary metaclass returned from `with_metaclass()`, such that it directly inherits from `type`, instead of inheriting from the target metaclass [1]. We depended on this detail, and the change caused .. code-block:: python TypeError('metaclass conflict: ...') to be raised when defining a class with `with_metaclass()`. We fix this by manually selecting the most derived metaclass, and including it in our temporary metaclass. Also, `__prepare__` is now defined on the temporary metaclass, in six 1.11.0 [2]. This allows us to skip our own definition of that method, when using six>=1.11.0. Fixes #228. Fixes #239. [1] <benjaminp/six#191> [2] <benjaminp/six#178>
I think the |
jeffwidman
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Oct 22, 2018
Bump `six` to `1.11.0`. Most changes do not affect us, but it's good to stay up to date. Also, we will likely start vendoring `enum34` in which case benjaminp/six#178 is needed. Note that this preserves the `kafka-python` customization from #979 which has been submitted upstream as benjaminp/six#176 but not yet merged.
jeffwidman
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to dpkp/kafka-python
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Oct 22, 2018
Bump `six` to `1.11.0`. Most changes do not affect us, but it's good to stay up to date. Also, we will likely start vendoring `enum34` in which case benjaminp/six#178 is needed. Note that this preserves the `kafka-python` customization from #979 which has been submitted upstream as benjaminp/six#176 but not yet merged.
jeffwidman
added a commit
to dpkp/kafka-python
that referenced
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Oct 22, 2018
Bump `six` to `1.11.0`. Most changes do not affect us, but it's good to stay up to date. Also, we will likely start vendoring `enum34` in which case benjaminp/six#178 is needed. Note that this preserves the `kafka-python` customization from #979 which has been submitted upstream as benjaminp/six#176 but not yet merged.
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Define
__prepare__()
inwith_metaclass()
's temporarymetaclass, and make sure that it passes the correct bases to the
real metaclass's
__prepare__()
.The temporary metaclass previously didn't extend the
__prepare__()
method, which meant that if the real metaclasshad a
__prepare__()
, it wouldn't get called correctly. Thiscould lead to bugs in Python 3 code.
The temporary metaclass's
__prepare__()
gets called withbases=(temporary_class,)
. Since there was no proxy in themiddle, that was getting passed directly to the real metaclass's
__prepare__()
. But then, if the real class's__prepare__()
method depended on the bases, the logic would be incorrect.
This was a problem in projects that use
enum
/enum34
andtry to use
with_metaclass(EnumMeta)
.enum34.EnumMeta
doesn'tdefine
__prepare__()
, since it is a Python 2 backport. Python3's
enum.EnumMeta
does define__prepare__()
, but originallydidn't depend at all on the bases. But starting in Python 3.6,
enum.EnumMeta.__prepare__()
will raiseTypeError
if thebases aren't valid for an enum subclass. Thus, a codebase that
was successfully using
enum
/enum34
andwith_metaclass(EnumMeta)
could break on Python 3.6.