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[PM-26177] Derive rotateable key set from PRF (3/3) #487
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Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,44 @@ | ||
use crate::{utils::stretch_key, CryptoError, SymmetricCryptoKey}; | ||
|
||
/// Takes the output of a PRF and derives a symmetric key | ||
pub fn derive_symmetric_key_from_prf(prf: &[u8]) -> Result<SymmetricCryptoKey, CryptoError> { | ||
let (secret, _) = prf | ||
.split_at_checked(32) | ||
.ok_or_else(|| CryptoError::InvalidKeyLen)?; | ||
let secret: [u8; 32] = secret.try_into().unwrap(); | ||
if secret.iter().all(|b| *b == b'\0') { | ||
return Err(CryptoError::ZeroNumber); | ||
} | ||
Ok(SymmetricCryptoKey::Aes256CbcHmacKey(stretch_key( | ||
&Box::pin(secret.into()), | ||
)?)) | ||
} | ||
|
||
#[cfg(test)] | ||
mod tests { | ||
use super::*; | ||
#[test] | ||
fn test_prf_succeeds() { | ||
let prf = [ | ||
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, | ||
24, 25, 26, 27, 28, 29, 30, 31, | ||
]; | ||
derive_symmetric_key_from_prf(&prf).unwrap(); | ||
} | ||
|
||
#[test] | ||
fn test_zero_key_fails() { | ||
let prf = [ | ||
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, | ||
0, 0, 0, | ||
]; | ||
let err = derive_symmetric_key_from_prf(&prf).unwrap_err(); | ||
assert!(matches!(err, CryptoError::ZeroNumber)); | ||
} | ||
#[test] | ||
fn test_short_prf_fails() { | ||
let prf = [0, 1, 2, 3, 4, 5, 6, 7, 8]; | ||
let err = derive_symmetric_key_from_prf(&prf).unwrap_err(); | ||
assert!(matches!(err, CryptoError::InvalidKeyLen)); | ||
} | ||
} |
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My suggestion here is very verbose, but "PRF key" alone suggests the "external key" (prf key) not the entire keyset.
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Yes, that's clearer. (I'll tweak the docs to be clearer too.)
If we wanted it shorter, we could establish a convention that
keyset
refers to a rotateable key set and name itderive_prf_user_keyset()
, which means a user [rotateable] key set protected by PRF, just likederive_pin_user_key()
above refers to a user key protected by a PIN. Thoughts?There was a problem hiding this comment.
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Seems good to me.