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pypi/pypi/-/matplotlib/3.4.1 #10483
pypi/pypi/-/matplotlib/3.4.1 #10483
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You can review the change introduced to the full definition at ClearlyDefined. |
@capfei This could be Declared as PSF-2.0. PyPI metadata is PSF. The license is a close enough match with references to PSF and Python customized, but main licensing text was not changed. https://matplotlib.org/stable/users/license.html. Thoughts? |
Same as #10486. Changing to PSF-2.0 |
@AE49 Thanks a lot for taking this up! After your changes, looks like the ClearlyDefined curation check was unsuccessful. How can we resolve that and complete the pull request? -- |
Conflicts have been resolved. |
@saheel1115 Validation is still failing for PSF-2.0 due to an issue with the bot. Will merge when resolved. Tracking in #11048. |
@capfei Thanks for the update! I'll pass it forward to others in my team. |
We discovered some errors in this curation when validating it: 2.2.2 licensed.declared with value "PSF-2.0" is not SPDX compliant |
We discovered some errors in this curation when validating it: 2.2.2 licensed.declared with value "PSF-2.0" is not SPDX compliant |
1 similar comment
We discovered some errors in this curation when validating it: 2.2.2 licensed.declared with value "PSF-2.0" is not SPDX compliant |
Conflicts have been resolved. |
Type: Auto
Summary:
pypi/pypi/-/matplotlib/3.4.1
Details:
Add OTHER license
Resolution:
Auto-generated curation. Newly harvested version 3.4.1 matches existing version 3.3.4.
Matching metadata: registryData.info.license: 'PSF'
Affected definitions: