[함헌규] sprint12#145
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heonq wants to merge 5 commits intocodeit-sprint-fullstack:next-함헌규from
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pers0n4
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Feb 27, 2025
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| onSuccess: () => { | ||
| if (initialValue) { | ||
| const changedFields: Partial<CreateProductRequest> = {}; | ||
| if (data.name !== initialValue.name) changedFields.name = data.name; | ||
| if (data.description !== initialValue.description) | ||
| changedFields.description = data.description; | ||
| if (data.price !== initialValue.price) | ||
| changedFields.price = data.price; | ||
| if (Object.keys(changedFields).length > 0) | ||
| return (mutation as EditMutation).mutate(changedFields); | ||
| } | ||
| return (mutation as CreateMutation).mutate({ | ||
| ...data, | ||
| images: [`https://${imageUrl}`], | ||
| }); | ||
| }, | ||
| }); |
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함수 구현체가 길어지면 인라인 콜백으로 사용하는 대신 함수를 따로 정의해보면 가시성을 높일 수 있을 것 같다는 면에서 좋아 보여요.
Comment on lines
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| if (data.name !== initialValue.name) changedFields.name = data.name; | ||
| if (data.description !== initialValue.description) | ||
| changedFields.description = data.description; | ||
| if (data.price !== initialValue.price) | ||
| changedFields.price = data.price; |
Contributor
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비슷한 모양의 코드가 반복되는데 반복문이나 함수형 프로그래밍적으로 접근해보면 어떨까요?
| async (error) => { | ||
| const originalRequest = error.config; | ||
|
|
||
| if (originalRequest.url === 'auth/refresh-token') { |
Contributor
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직관적으로 파악하기 힘든 조건의 경우는 변수 또는 함수로 추상화해주면 파악하기 쉬워질 것 같아요.
e.g.
const hasRefreshTokenRequestFailed = originalRequest.url === 'auth/refresh-token'
if (hasRefreshTokenRequestFailed) {}
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