how do i schema.parse with returned type from schema?

[u007]

hi

i tried to get return type of zod.parse using the code below, but visual code does not give any autocomplete on aaa.
did I do anything wrong?

thank you

const inputSchema = z.object({
  page: z.string().default('1').transform((v) => parseInt(v)),
  limit: z.string().default('10').transform((v) => parseInt(v)),
})

export const parseTest = async (schema: ZodType, data: any): Promise<z.infer<typeof schema>> => {
  return schema.parse(schema, data)
}

const aaa = await parseTest(inputSchema,{page: '1', limit: '10'})

[JacobWeisenburger]

I think you need to use a generic. <Schema extends z.ZodType>

Let me know if you have any questions.

const inputSchema = z.object( {
    page: z.string().default( '1' ).transform( ( v ) => parseInt( v ) ),
    limit: z.string().default( '10' ).transform( ( v ) => parseInt( v ) ),
} )

export const parseTest = async <Schema extends z.ZodType> (
    schema: Schema, data: any
): Promise<z.infer<Schema>> => {
    return schema.parse( schema, data )
}

const aaa = await parseTest( inputSchema, { page: '1', limit: '10' } )
type AAA = typeof aaa
// type AAA = { page: number; limit: number; }

console.log( aaa ) // { page: 1, limit: 10 }