How to raise a JSON:API exception with a custom status code?

[Nekidev]

What the title says. For example, I can raise a ValidationError with forbidden as the code, but the status code will be 400 (not 403).

from rest_framework_json_api import serializers

def my_error_view(request):
    """
    This view raises an exception which will be formatted as a JSON:API error object.
    """

    raise serializers.ValidationError(
        detail="You need the `access_this_view` permission to access this resource.",
        code="forbidden"
    )

Any request to that endpoint in this example will return a 400 error response with a forbidden code. Is there any way to specify a status code?

[sliverc]

Django REST framework has different type of exceptions for different status codes. ValidationError will always return a status code 400. In case you want to have 403 status code you need to raise a PermissionDenied exception.