Running simple-cache-example gives an error, flag 'v' was defined more than once

[YuqingXiong]

Describe the bug
when i run the example "simple_cache", i find an error "ERROR: flag 'v' was defined more than once"

To Reproduce
Steps to reproduce the behavior:

1. cd CacheLib/examples/simple_cache
2. ./build.sh
3. ./build/simple-cache-example
4. See error

Expected behavior
i want to run this example.

Screenshots

Desktop (please complete the following information):

• Ubuntu 22.04.3 LTS
• CacheLib tag: v20240312_RC

[therealgymmy]

can you share more details regarding your linux setup? Which ubuntu version is this?

[guaguastandup]

same question, same cachelib tag, I am using ubuntu22.04

can you share more details regarding your linux setup? Which ubuntu version is this?

[YuqingXiong]

same question, same cachelib tag, I am using ubuntu22.04

can you share more details regarding your linux setup? Which ubuntu version is this?

me too. I am using Ubuntu 22.04.3 LTS

[YuqingXiong]

In fact, I have an inelegant solution.

I just commented the error output code, like this:

Then, return back Cachelib directory, and remove all build files:
rm -rf ./build-*

Finally, again to build, but not use git:
./contrib/build.sh -d -j -v -S

This error will not apper, but I think it might cause other bugs in the future.

[YuqingXiong]

can you share more details regarding your linux setup? Which ubuntu version is this?

Of course, this is my system information. I use the Ubuntu 22.04.3 LTS and g++ (Ubuntu 11.4.0-1ubuntu1~22.04) 11.4.0

[MaoZiming]

Same problem