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'use strict';
const gulp = require('gulp');
const inline = require('gulp-inline-source');
gulp.task('inline', () => {
return gulp.src('dist/**/*.html')
.pipe(inline({
compress: false
}))
.pipe(gulp.dest('dist'));
});
Throws an error when finding file like google0b725740ac54caf0.html - it is used to confirm website ownership in Google Webmaster dashboard. Content is just one line, something like: google-site-verification: google0b725740ac54caf0.html
And here is the error itself:
[12:51:52] Starting 'inline'...
events.js:154
throw er; // Unhandled 'error' event
^
Error: ENOENT: no such file or directory, open '/home/pesochek/docker-lm/google-site-verification: google0b725740ac54caf0.html'
at Error (native)
Can be fixed by defining gulp.src
this way, but it doesn't seem to be correct, shouldn't such files be simply ignored by gulp-inline-source itself? ['dist/**/*.html', '!dist/**/{google,y_key_}*.html']
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