Raza khan9639 (saadfareed#53)

* Hactoberfest Contribution Problem#13

* Hactoberfest Contribution Problem#13

* Hacktoberfest Contribution Problem saadfareed#12

* Problem saadfareed#9 Javascript

* LeetCode Problem #984

JS/Restrained3a3b.js

@@ -0,0 +1,48 @@
+//Name: Raza Mohayyuddin
+
+//Username: RazaKhan9639
+
+//Approach: First create a variable rt to store the required string. After that use if else conditions to to compare the numbers of 'a' and 'b' in a usual order of counting and store the string in rt by appending 2b then a or 2a then b. Time complexity : n, where n is the count of a or b , and space complexity is normal O(1).
+
+var strWithout3a3b = function (a, b) {
+  let rt = ""; //Required String
+  while (a > 0 || b > 0) {
+    // More 'b', append "bba"
+    if (a < b) {
+      if (b-- > 0) {
+        rt += "b";
+      }
+      if (b-- > 0) {
+        rt += "b";
+      }
+      if (a-- > 0) {
+        rt += "a";
+      }
+    }
+
+    // More 'a', append "aab"
+    else if (b < a) {
+      if (a-- > 0) {
+        rt += "a";
+      }
+      if (a-- > 0) {
+        rt += "a";
+      }
+      if (b-- > 0) {
+        rt += "b";
+      }
+    }
+
+    // Equal number of 'a' and 'b'
+    // append "ab"
+    else {
+      if (a-- > 0) {
+        rt += "a";
+      }
+      if (b-- > 0) {
+        rt += "b";
+      }
+    }
+  }
+  return rt;
+};