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dfs - have the parameter on the go as you update!
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Leet_Code/medium/988_Smallest_String_Starting_From_Leaf.py
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""" | ||
You are given the root of a binary tree where each | ||
node has a value in the range [0, 25] representing | ||
the letters 'a' to 'z'. | ||
Return the lexicographically smallest string that starts | ||
at a leaf of this tree and ends at the root. | ||
As a reminder, any shorter prefix of a string | ||
is lexicographically smaller. | ||
For example, "ab" is lexicographically smaller than "aba". | ||
A leaf of a node is a node that has no children. | ||
Example 1: | ||
Input: root = [0,1,2,3,4,3,4] | ||
Output: "dba" | ||
Example 2: | ||
Input: root = [25,1,3,1,3,0,2] | ||
Output: "adz" | ||
Example 3: | ||
Input: root = [2,2,1,null,1,0,null,0] | ||
Output: "abc" | ||
Constraints: | ||
The number of nodes in the tree | ||
is in the range [1, 8500]. | ||
0 <= Node.val <= 25 | ||
Takeaway: | ||
dfs - have the parameter on the go as you update! | ||
""" | ||
# Definition for a binary tree node. | ||
class TreeNode: | ||
def __init__(self, val=0, left=None, right=None): | ||
self.val = val | ||
self.left = left | ||
self.right = right | ||
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class Solution: | ||
def smallestFromLeaf_(self, root: TreeNode) -> str: | ||
# Does Not Work! | ||
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res = [] | ||
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def dfs(node, path): | ||
if not node: | ||
res.append(path) | ||
return | ||
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dfs(node.left, path + [node.val]) | ||
dfs(node.right, path + [node.val]) | ||
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dfs(root, []) | ||
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shortest = min([elem[::-1] for elem in res]) | ||
print(res) | ||
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# ? | ||
char_map = {0: "a"} | ||
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converter = lambda x: chr(ord("a") + x) | ||
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return "".join([converter(elem) for elem in shortest]) | ||
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def smallestFromLeaf(self, root: TreeNode) -> str: | ||
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# Helper function to perform DFS | ||
# it has the smallest as a paramater, because we | ||
# will update it | ||
def dfs(node, path, smallest): | ||
if not node: | ||
return | ||
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# Append current node's character | ||
# to the path | ||
path.append(chr(node.val + ord('a'))) | ||
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# If it's a leaf node, reverse the | ||
# path and compare | ||
if not node.left and not node.right: | ||
# reverse path to get string | ||
current_string = ''.join(path[::-1]) | ||
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smallest[0] = min(smallest[0], current_string) | ||
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# Recursively traverse left and | ||
# right subtrees | ||
dfs(node.left, path, smallest) | ||
dfs(node.right, path, smallest) | ||
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# Backtrack: remove the current node's | ||
# character from the path | ||
path.pop() | ||
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# Initialize smallest string | ||
# as a large value | ||
# Store smallest string found | ||
smallest = [chr(ord('z') + 1)] | ||
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# Start DFS from the root | ||
# with an empty path | ||
dfs(root, [], smallest) | ||
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return smallest[0] |