Description
Search Terms
Suggestion
Based on https://stackoverflow.com/questions/56680049, it seems mixin classes can't be used inside other mixins.
It'd be great if, in that example, the outer mixin would be able to successfully use the props and types from the Sizeable mixin.
Note, in the example, Sizeable
is a class with a default Base class applied, and .mixin
is the mixin function used to create it.
Basically, the following (in JS, and simplified):
function SizeableMixin(Base = class {}) {
return class Sizeable extends Base {...}
}
const Sizeable = SizeableMixin()
Sizeable.mixin = SizeableMixin
export default Sizeable
So it's just a regular class-factory mixin (with a default application so that it is easy to extend like a normal class when used as a base class).
Use Cases
To be able to use Mixins anywhere, including inside other mixins.
Examples
import Sizeable from './Sizeable'
function FooMixin<T extends Constructor>(Base: T) {
const Parent = Sizeable.mixin(Base)
return class Foo extends Parent { ... } // ERROR, [Parent] is not a constructor function.
}
const Foo = FooMixin()
Foo.mixin = FooMixin // ignore types here, for now
export default Foo
But actually, Parent
is a constructor. We know it is. It'd be great to use it.
In the Foo mixin, I should at least be able to correctly use Sizeable properties and methods, as if Sizeable were the base class.
Checklist
My suggestion meets these guidelines:
- This wouldn't be a breaking change in existing TypeScript/JavaScript code
- This wouldn't change the runtime behavior of existing JavaScript code
- This could be implemented without emitting different JS based on the types of the expressions
- This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, etc.)
- This feature would agree with the rest of TypeScript's Design Goals.