WIP: add refactoring: string concatenation to template literals

[bigaru]

Fixes #18267

[ajafff]

This function should also covert octal escape sequences to some other representation (hexadecimal?) as they are not allowed in template strings

[bigaru]

thank you, I missed that one
@ajafff Do you know by chance how to get raw representation of normal string (not of template literal)?

Since escape sequences are already interpreted, it's not possible to catch with regex.

const ex7 = "Unicode \u0023 \u{0023} " + "Hex \x23 " + " Octal \43";
// Unicode # # Hex # Octal # 
const transformed7 = ex7.replace(/\\([0-7]+)/g, (_whole, n) =>"eee");
// Unicode # # Hex # Octal # 
// Therefore, regex fails

With String.raw it's possible to get raw representation

const rawVersion = String.raw`Unicode \u0023 \u{0023} Hex \x23  Octal \43`;
// Unicode \u0023 \u{0023} Hex \x23  Octal \43

But if I use String.raw as function, it behaves differently.

const ex9 = ["Unicode \u0023 \u{0023} Hex \x23  Octal \43"]
const transformed9 = String.raw({ raw: ex9, ...ex9 });
// Unicode # # Hex #  Octal 43

[bigaru]

I found a solution but I am not sure if it's the right way to solve it.

[ajafff]

node.getText() is the correct solution to get the raw string content. To avoid unnecessary work, consider passing the SourceFile as argument to it.

[RyanCavanaugh]

Closing WIP PRs for housekeeping - feel free to open a fresh one if you have something you think might be mergeable. Thanks!