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Base: make TwicePrecision more accurate
Update the arithmetic code to use algorithms published since twiceprecision.jl got written. Handle complex numbers. Prevent some harmful promotions. Some of the introduced extended precision arithmetic code will also be used in `base/div.jl` to tackle issue JuliaLang#49450 with PR JuliaLang#49561. Results: The example in JuliaLang#33677 still gives the same result. I wasn't able to evaluate JuliaLang#23497 because of how much Julia changed in the meantime. Proof that JuliaLang#26553 is fixed: ```julia-repl julia> const TwicePrecision = Base.TwicePrecision Base.TwicePrecision julia> a = TwicePrecision{Float64}(0.42857142857142855, 2.3790493384824782e-17) Base.TwicePrecision{Float64}(0.42857142857142855, 2.3790493384824782e-17) julia> b = TwicePrecision{Float64}(3.4, 8.881784197001253e-17) Base.TwicePrecision{Float64}(3.4, 8.881784197001253e-17) julia> a_minus_b_inexact = Tuple(a - b) (-2.9714285714285715, 1.0150610510858574e-16) julia> BigFloat(a) == sum(map(BigFloat, Tuple(a))) true julia> BigFloat(b) == sum(map(BigFloat, Tuple(b))) true julia> a_minus_b = BigFloat(a) - BigFloat(b) -2.971428571428571428571428571428577679589762353999797347402693647078382455095635 julia> Float64(a_minus_b) == first(a_minus_b_inexact) true julia> Float64(a_minus_b - Float64(a_minus_b)) == a_minus_b_inexact[begin + 1] true ``` Fixes JuliaLang#26553 Updates JuliaLang#49589
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