Fix bug of printerrormsg #128
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When printerrormsg() was executed, the specification was that it would unconditionally set errmsgflg to 1 and cause a precompile error.
This is an error. When printerrormsg() is executed, the function basically terminates abnormally, but depending on the conditions, it may terminate normally.
Therefore, it was corrected so that a precompile error is generated only when an abnormal termination occurs.