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Both DataFrames should return the same thing. Order should not matter here. I suppose this is happening based on whether or not the first column has any missing values?
This happens for the other aggregation methods max and sum
Expected Output
For consistency, both should output the same thing.
In [63]: >>> df = pd.DataFrame({'A':['a', None], 'B':['a', 'b']})
...: >>> df.min()
Out[63]:
B a
dtype: object
In [64]: df[['B', 'A']].min()
Out[64]:
B a
dtype: object
In [65]: pd.__version__
Out[65]: '0.26.0.dev0+593.g9d45934af'
Code Sample, a copy-pastable example if possible
Problem description
Both DataFrames should return the same thing. Order should not matter here. I suppose this is happening based on whether or not the first column has any missing values?
This happens for the other aggregation methods
max
andsum
Expected Output
For consistency, both should output the same thing.
Output of
pd.show_versions()
pandas: 0.20.2
pytest: 3.0.7
pip: 9.0.1
setuptools: 35.0.2
Cython: 0.25.2
numpy: 1.13.0
scipy: 0.19.0
xarray: None
IPython: 6.0.0
sphinx: 1.5.5
patsy: 0.4.1
dateutil: 2.6.0
pytz: 2017.2
blosc: None
bottleneck: 1.2.0
tables: 3.4.2
numexpr: 2.6.2
feather: None
matplotlib: 2.0.2
openpyxl: 2.4.7
xlrd: 1.0.0
xlwt: 1.2.0
xlsxwriter: 0.9.6
lxml: 3.7.3
bs4: 4.6.0
html5lib: 0.999999999
sqlalchemy: 1.1.9
pymysql: None
psycopg2: None
jinja2: 2.9.6
s3fs: None
pandas_gbq: None
pandas_datareader: 0.3.0.post
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