BUG: Inconsistent multiplication of bool times Timedelta

[Dr-Irv]

Pandas version checks

• I have checked that this issue has not already been reported.

• I have confirmed this bug exists on the latest version of pandas.

• I have confirmed this bug exists on the main branch of pandas.

Reproducible Example

import datetime as dt
import pandas as pd
dt.timedelta(days=1) * True  #  Works
pd.Timedelta("1 day") * True  # Fails in 2.3.2 and in main
pd.Series([True, False]) * pd.timedelta_range(start="1 day", end="2 days")  # Works in 2.3.2, fails in main

Issue Description

See above. Multiplying a bool times a Timedelta is inconsistent.

In version 2.3.2, you can't multiply a single bool and a pd.Timedelta object, but you can multiply them if they are in a Series.

In main ('3.0.0.dev0+2389.g452c7fb6a4'), you cannot multiply when in a Series.

Note that using datetime.timedelta, you can multiply a boolean with a Timedelta

Expected Behavior

I think multiplication of a Timedelta times a bool should work like it does for datetime.timedelta

Installed Versions

INSTALLED VERSIONS

commit : 452c7fb
python : 3.11.13
python-bits : 64
OS : Windows
OS-release : 10
Version : 10.0.26100
machine : AMD64
processor : Intel64 Family 6 Model 183 Stepping 1, GenuineIntel
byteorder : little
LC_ALL : None
LANG : None
LOCALE : English_United States.1252

pandas : 3.0.0.dev0+2389.g452c7fb6a4
numpy : 2.3.3
dateutil : 2.9.0.post0
pip : 25.1
Cython : None
sphinx : None
IPython : None
adbc-driver-postgresql: None
adbc-driver-sqlite : None
bs4 : 4.13.5
bottleneck : None
fastparquet : None
fsspec : None
html5lib : 1.1
hypothesis : None
gcsfs : None
jinja2 : 3.1.6
lxml.etree : 6.0.1
matplotlib : 3.10.6
numba : None
numexpr : 2.12.1
odfpy : None
openpyxl : 3.1.5
psycopg2 : None
pymysql : None
pyarrow : 21.0.0
pyiceberg : None
pyreadstat : 1.3.1
pytest : N/A
python-calamine : None
pytz : 2025.2
pyxlsb : 1.0.10
s3fs : None
scipy : 1.16.1
sqlalchemy : 2.0.43
tables : 3.10.2
tabulate : 0.9.0
xarray : 2025.9.0
xlrd : 2.0.2
xlsxwriter : 3.2.5
zstandard : 0.24.0
qtpy : None
pyqt5 : None

[Dr-Irv]

@jbrockmendel I assigned to you - not sure if that is correct or not.

[jbrockmendel]

We disabled that intentionally in #62248

[Dr-Irv]

We disabled that intentionally in #62248

OK, but does it make sense that we can multiply dt.timedelta and bool, but not pd.Timedelta and bool ??

[jbrockmendel]

i think it doesn't make sense that dt.timedelta*bool works.

[Dr-Irv]

i think it doesn't make sense that dt.timedelta*bool works.

Well, we're then inconsistent with numpy as well:

>>> import numpy as np
>>> np.timedelta64(1, "D") * True
np.timedelta64(1,'D')
>>> np.timedelta64(1, "D") * False
np.timedelta64(0,'D')

My sense here is that if both python and numpy are supporting multiplying a bool times a timedelta, then pandas should do the same.