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If you run the following code in a JupyterLab cell:
import plotly.express as px import pandas as pd df = pd.DataFrame({'A': [1, 2, 3], 'B': [3, 4, 5]}) fig = px.line(df, x='A', y='B') fig.show(renderer="iframe")
You get the following error:
--------------------------------------------------------------------------- TypeError Traceback (most recent call last) Cell In[8], line 5 3 df = pd.DataFrame({'A': [1, 2, 3], 'B': [3, 4, 5]}) 4 fig = px.line(df, x='A', y='B') ----> 5 fig.show(renderer="iframe") File ~/temps/2023-01-22-1674410931/venv/lib/python3.9/site-packages/plotly/basedatatypes.py:3390, in BaseFigure.show(self, *args, **kwargs) 3357 """ 3358 Show a figure using either the default renderer(s) or the renderer(s) 3359 specified by the renderer argument (...) 3386 None 3387 """ 3388 import plotly.io as pio -> 3390 return pio.show(self, *args, **kwargs) File ~/temps/2023-01-22-1674410931/venv/lib/python3.9/site-packages/plotly/io/_renderers.py:388, in show(fig, renderer, validate, **kwargs) 385 fig_dict = validate_coerce_fig_to_dict(fig, validate) 387 # Mimetype renderers --> 388 bundle = renderers._build_mime_bundle(fig_dict, renderers_string=renderer, **kwargs) 389 if bundle: 390 if not ipython_display: File ~/temps/2023-01-22-1674410931/venv/lib/python3.9/site-packages/plotly/io/_renderers.py:296, in RenderersConfig._build_mime_bundle(self, fig_dict, renderers_string, **kwargs) 293 if hasattr(renderer, k): 294 setattr(renderer, k, v) --> 296 bundle.update(renderer.to_mimebundle(fig_dict)) 298 return bundle File ~/temps/2023-01-22-1674410931/venv/lib/python3.9/site-packages/plotly/io/_base_renderers.py:570, in IFrameRenderer.to_mimebundle(self, fig_dict) 567 iframe_height = str(525 + iframe_buffer) + "px" 569 # Build filename using ipython cell number --> 570 filename = self.build_filename() 572 # Make directory for 573 try: File ~/temps/2023-01-22-1674410931/venv/lib/python3.9/site-packages/plotly/io/_base_renderers.py:613, in IFrameRenderer.build_filename(self) 611 ip = IPython.get_ipython() if IPython else None 612 if ip: --> 613 cell_number = next(ip.history_manager.get_tail(1), (0, -1, ""))[1] + 1 614 else: 615 cell_number = 0 TypeError: 'list' object is not an iterator
If you remove renderer="iframe", this completes correctly.
renderer="iframe"
Relevant versions pip list | grep -E 'pandas|jupyter|plotly':
pip list | grep -E 'pandas|jupyter|plotly'
jupyter_client 7.4.9 jupyter_core 5.1.3 jupyter-events 0.6.3 jupyter_server 2.1.0 jupyter_server_terminals 0.4.4 jupyterlab 3.5.2 jupyterlab-pygments 0.2.2 jupyterlab_server 2.19.0 pandas 1.5.3 plotly 5.12.0
I have verified this bug is reproducible on both Mac Safari and Mac Chrome.
Let me know if any other additional information is helpful!
The text was updated successfully, but these errors were encountered:
Thanks for the clear bug report! I have a fix and will release it this week, as early as tomorrow :)
Sorry, something went wrong.
Successfully merging a pull request may close this issue.
If you run the following code in a JupyterLab cell:
You get the following error:
If you remove
renderer="iframe"
, this completes correctly.Relevant versions
pip list | grep -E 'pandas|jupyter|plotly'
:I have verified this bug is reproducible on both Mac Safari and Mac Chrome.
Let me know if any other additional information is helpful!
The text was updated successfully, but these errors were encountered: