Fix chruby-exec sourcing chruby.sh

chruby-exec works as follows:

1. test for presence of chruby with `command -v chruby >/dev/null`
2. source `chruby.sh` if chruby is not loaded
3. execute `chruby $ruby && $command` in a subshell

The problem is that sourced functions, unlike environmental variables,
are not 'inherited' by subshells.
(It is true at least in Ubuntu 12.04 LTS, where I tested this)

With "basic setup" you copy `chruby.sh` to `/etc/profile.d`, and this
`chruby.sh` sources `/usr/share/local/chruby/chruby.sh`
Then, when you invoke `chruby_exec` it works just fine, because
`/usr/share/local/chruby/chruby.sh` is sourced automaticaly by bash
through `/etc/profile` initialization script (which sources
`/etc/profile.d/chruby.sh`)

It would be great if you consider moving the process of sourcing
`/usr/share/local/chruby/chruby.sh` from the top of `chruby_exec` to a
command executed by a subshell. It would allow to use `chruby_exec`
without needing to source `/usr/local/chruby/chruby.sh` with shell init
scripts (`/etc/profile.d/chruby.sh`)

About function inheritance in a subshells

You could check it with the following setup:

    # set_func.sh:
    function test_func()
    {
        0
    }

    # file get_func.sh:
    source ./set_func.sh

    type test_func | head -1

    exec "$SHELL" -i -l -c "type test_func | head -1"

and then:

    $ ./get_func.sh
    test_func is a function
    bash: type: test_func: not found

bin/chruby-exec

@@ -1,7 +1,5 @@
 #!/usr/bin/env bash
 
-source "${0%/*}/../share/chruby/chruby.sh"
-
 case "$1" in
 	-h|--help)
 		echo "usage: chruby-exec RUBY [RUBYOPTS] -- COMMAND [ARGS...]"
@@ -33,7 +31,9 @@ if (( $# == 0 )); then
 	exit 1
 fi
 
-command="chruby $(printf "%q " "${argv[@]}") && $(printf "%q " "$@")"
+chruby_sh="${0%/*}/../share/chruby/chruby.sh"
+source_command="command -v chruby >/dev/null || source $chruby_sh"
+command="$source_command; chruby $(printf "%q " "${argv[@]}") && $(printf "%q " "$@")"
 
 if [[ -t 0 ]]; then exec "$SHELL" -i -l -c "$command"
 else                exec "$SHELL"    -l -c "$command"