message_filters.Subscriber

[schlichtanders]

message_filters.Subscriber in python doesn't support either .unregister() as rospy.Subscriber or .unsubscribe() as it is implemented in the cpp variant.

[dirk-thomas]

A message_filters.Subscriber has a public member variable pub which stores a rospy publisher. You might just want to invoke unsubscribe() on that?

message_filters_subscriber.sub.unsubscribe()

[schlichtanders]

Thank you very much for the fast response.
I guess you mean message_filters_subscriber.sub.unregister() and yes this
is what I searched for.

Thanks

On 23 March 2014 07:18, Dirk Thomas notifications@github.com wrote:

A message_filters.Subscriber has a public member variable pub which
stores a rospy publisher. You might just want to invoke unsubscribe() on
that?

message_filters_subscriber.sub.unsubscribe()

Reply to this email directly or view it on GitHubhttps://github.com//issues/380#issuecomment-38375200
.

[tfoote]

I think this is resolved. Closing. Please comment if not and we can reopen.