Can't import super

[wthrowe]

I'm not sure if this falls into the realm of something needing an RFC or not, but I expected this to work:

mod a {
    use super as foo;
}

but it gives error: expected identifier, found keyword super``.

If I do it in an import list I get a different error:

mod a {
    use super::{self as foo};
}

error: unresolved import super. There is no superin???``

(I suppose this also applies to self, but I can't think of a reason to do that.)

Edit: This seems to work as a substitute:

mod a {
    mod foo { pub use super::super::*; }
}

[steveklabnik]

@rust-lang/lang, what do you think about this?

[nikomatsakis]

I vaguely expect use super as foo to work as well as use super::{self as foo}

This error message "error: unresolved import super. There is no super in ???" DEFINITELY seems subpar.

[jseyfried]

c.f. #39330 (comment)

[ordian]

Any chance this being fixed in rust 2018?

[tv42]

I stumbled on this today. This is clearly allowed by the grammar in reference, and either should work or the reference needs to be changed:

UseDeclaration :
use UseTree ;

UseTree :
(SimplePath? ::)? *
| (SimplePath? ::)? { (UseTree ( , UseTree )* ,?)? }
| SimplePath ( as ( IDENTIFIER | _ ) )?

SimplePath :
::? SimplePathSegment (:: SimplePathSegment)*

SimplePathSegment :
IDENTIFIER | super | self | crate | $crate

[tv42]

Alternate perhaps simpler workaround:

use super::super::name_of_my_parent;
use super::super::name_of_my_parent as newname;