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#[derive(Clone)] always require generic arguments to be Clone, which is too restrictive #32673

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@VFLashM

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@VFLashM

[derive(Clone)] should not require generic arguments to be Clone if it's not necessary.

use std::rc::Rc;

struct S;

#[derive(Clone)]
struct Works(Rc<S>);

#[derive(Clone)]
struct Fails<T>(Rc<T>);

fn main() {
    let w = Works(Rc::new(S));
    w.clone(); // ok

    let f = Fails(Rc::new(S));
    f.clone(); // fails
}

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