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There is no reason it should not work, though. The a.type <:< a.type with B is true and recognized by the compiler, as the following demonstrates, which works in all versions:
The following works in 2.12.6, but fails in both 2.12.7 and 2.12.8:
There is no reason it should not work, though. The
a.type <:< a.type with B
is true and recognized by the compiler, as the following demonstrates, which works in all versions:These subtyping relationships are sometimes useful; for a concrete example see: https://github.com/epfldata/squid/blob/7df295499b7371980b5574f87e0f56f2c20e3a5d/core/src/main/scala/squid/quasi/QuasiBase.scala#L133-L136
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