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[Haskell] match (*, @, and #) in keyword.operator.haskell #2272

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[Haskell] match (*, @, and #) in keyword.operator.haskell #2272

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2 changes: 1 addition & 1 deletion Haskell/Haskell.sublime-syntax
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Original file line number Diff line number Diff line change
Expand Up @@ -179,7 +179,7 @@ contexts:
scope: constant.other.haskell
- include: comments
- include: infix_op
- match: '[|!%$?~+:\-.=</>\\]+'
- match: '[|!%$*@#?~+:\-.=</>\\]+'
comment: In case this regex seems overly general, note that Haskell permits the definition of new operators which can be nearly any string of punctuation characters, such as $%^&*.
scope: keyword.operator.haskell
- match: ","
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22 changes: 22 additions & 0 deletions Haskell/syntax_test_haskell.hs
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Expand Up @@ -186,3 +186,25 @@
0XdeafBEEF42
-- ^^^^^^^^^^^^ constant.numeric.integer.hexadecimal
-- ^^ punctuation.definition.numeric.base

data Outrageous =
Flipper Record
| Int :! Int
| Double :@ Double
-- ^ keyword.operator.haskell
| Int `Quux` Double
| String :# Record
-- ^ keyword.operator.haskell
| Simple :$ Outrageous
| DontDoThis { outrageousInt :: Int, outrageousString :: String }
deriving (Eq, Ord, Generic)
deriving (Read, Show) via (Quiet Outrageous)

genSimple :: Gen Simple
genSimple =
Simple
<$> genInt
<*> genString
-- ^ keyword.operator.haskell
<*> genDouble
<*> genRational