Generate types similar to RecipeVariants, but with string literals

[laura-asimov]

I'm looking for a way to generate the type from a recipe and have it include only the string literals
I currently generate the type using export type TextVariants = RecipeVariants<typeof textRecipe>;

In this scenario I'm looking to export the type as
export type TextVariants = { color: 'light' | 'dark' };

Is there a way to generate this type?

[daformat]

RecipeVariants includes undefined, here's what I do when I need something like this:

export type MaybeTextVariants = RecipeVariants<typeof textRecipe>;
export type TextVariants = Exclude<MaybeTextVariants, undefined>;
export type TextColor = TextVariants['color'];

I think you can go with just Exclude<MaybeTextVariants, undefined> in your case? The types shown in intellisense are confusing, but they are working as expected, hope this helps!

[laura-asimov]

@daformat Thank you!!
This is exactly what I was looking for, and for some reason it returns the string literals:

[laura-asimov]

For some reason the types in intellisense revert back to being confusing when using type intersection:

[askoufis]

@laura-asimov Typescript will sometimes leave complex types un-evaluated until it actually needs to evaluate them. It can sometimes helps to wrap these types in a prettify type that forces typescript to expand the type completely. In some cases this doesn't always work though.

type Prettify<T> = {
  [K in keyof T]: T[K]
} & {}