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Merge pull request #1 from vbertone/master
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Fixing bug in the massive NLO CC coefficient functions
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vbertone authored Sep 24, 2020
2 parents 80c83e3 + 1e057d4 commit 2d3c7a8
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Binary file modified doc/pdfs/CC_observables_def.pdf
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24 changes: 8 additions & 16 deletions doc/sources/DIS.tex
Original file line number Diff line number Diff line change
Expand Up @@ -492,7 +492,7 @@ \subsubsection{Charged Current Coefficient Functions}
z)}{1-z}\right]_++
2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\left[\frac{1}{1-z}\right]_+\\
\\ &+& \displaystyle
\frac{\lambda-1}{\lambda^2}\left[\frac{1}{1-\lambda z}\right]_+
\frac{\lambda-1}{\lambda^2}\left[\frac{1}{1-\lambda z}\right]
+\frac{1}{2}\left[\frac{1-z}{(1-\lambda z)^2}\right]_+\bigg\}
\end{array}\,,
\end{equation}
Expand All @@ -509,7 +509,7 @@ \subsubsection{Charged Current Coefficient Functions}
2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\left[\frac{1}{1-z}\right]_+\\
\\ &+& \displaystyle
\frac{2\lambda^2-\lambda-1}{\lambda}\left[\frac{1}{1-\lambda
z}\right]_+ +\frac{1}{2}\left[\frac{1-z}{(1-\lambda
z}\right] +\frac{1}{2}\left[\frac{1-z}{(1-\lambda
z)^2}\right]_+\bigg\}
\end{array}\,,
\end{equation}
Expand All @@ -525,7 +525,7 @@ \subsubsection{Charged Current Coefficient Functions}
\left[\frac{2\ln(1-z)-\ln(1-\lambda z)}{1-z}\right]_++
2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\left[\frac{1}{1-z}\right]_+\\
\\ &+& \displaystyle \frac{\lambda-1}{\lambda}\left[\frac{1}{1-\lambda
z}\right]_+ +\frac{1}{2}\left[\frac{1-z}{(1-\lambda
z}\right] +\frac{1}{2}\left[\frac{1-z}{(1-\lambda
z)^2}\right]_+\bigg\}
\end{array}\,,
\end{equation}
Expand All @@ -541,7 +541,7 @@ \subsubsection{Charged Current Coefficient Functions}
z)\right)(1+z)+3\\ \\ &+&\displaystyle 2
\left[\frac{2\ln(1-z)-\ln(1-\lambda z)}{1-z}\right]_++ 2
\left(-1+\ln\frac{K_F^2}{\lambda}\right)\left[\frac{1}{1-z}\right]_+\\
\\ &-& \displaystyle 2\left[\frac{1}{1-\lambda z}\right]_+
\\ &-& \displaystyle 2\left[\frac{1}{1-\lambda z}\right]
+\frac{1}{2}\left[\frac{1-z}{(1-\lambda z)^2}\right]_+\bigg\} + 2C_F
\left[\lambda K_A \delta(1-z) + (1+\lambda)z\right]
\end{array}\,.
Expand Down Expand Up @@ -574,10 +574,6 @@ \subsubsection{Charged Current Coefficient Functions}
-\int_0^xdz\frac{\ln(1-z)}{1-z} = \frac12
\ln^2(1-x)\,,
\end{equation}
\begin{equation}
-\int_0^x\frac{dz}{1-\lambda z} =
\frac{1}{\lambda}\ln(1-\lambda x)\,,
\end{equation}
\begin{equation}
-\int_0^xdz\frac{1-z}{(1-\lambda z)^2} =
\frac{1}{\lambda^2}\ln(1-\lambda
Expand All @@ -598,8 +594,7 @@ \subsubsection{Charged Current Coefficient Functions}
C^{(1)}_{1,q}&\rightarrow& \displaystyle
C^{(1)}_{1,q} +
2C_F\bigg[2\ln^2(1-x)-2R(x)+2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\ln(1-x)\\
\\ &&\displaystyle +\frac{\lambda-1}{\lambda^3}\ln(1-\lambda
x)+\frac{1}{2\lambda^2}\ln(1-\lambda
\\ &&\displaystyle +\frac{1}{2\lambda^2}\ln(1-\lambda
x)+\frac{1-\lambda}{2\lambda}\frac{x}{1-\lambda x}\bigg]\delta(1-z)
\end{array}\,,
\end{equation}
Expand All @@ -609,8 +604,7 @@ \subsubsection{Charged Current Coefficient Functions}
C^{(1)}_{2,q} +
2C_F\bigg[2\ln^2(1-x)-2R(x)+2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\ln(1-x)\\
\\ &&\displaystyle
+\frac{2\lambda^2-\lambda-1}{\lambda^2}\ln(1-\lambda
x)+\frac{1}{2\lambda^2}\ln(1-\lambda
+\frac{1}{2\lambda^2}\ln(1-\lambda
x)+\frac{1-\lambda}{2\lambda}\frac{x}{1-\lambda x}\bigg]\delta(1-z)
\end{array}\,,
\end{equation}
Expand All @@ -619,8 +613,7 @@ \subsubsection{Charged Current Coefficient Functions}
C^{(1)}_{3,q}&\rightarrow& \displaystyle
C^{(1)}_{3,q} +
2C_F\bigg[2\ln^2(1-x)-2R(x)+2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\ln(1-x)\\
\\ &&\displaystyle +\frac{\lambda-1}{\lambda^2}\ln(1-\lambda
x)+\frac{1}{2\lambda^2}\ln(1-\lambda
\\ &&\displaystyle +\frac{1}{2\lambda^2}\ln(1-\lambda
x)+\frac{1-\lambda}{2\lambda}\frac{x}{1-\lambda x}\bigg]\delta(1-z)
\end{array}\,,
\end{equation}
Expand All @@ -629,8 +622,7 @@ \subsubsection{Charged Current Coefficient Functions}
C^{(1)}_{L,q}&\rightarrow& \displaystyle
C^{(1)}_{L,q} +
2C_F(1-\lambda)\bigg[2\ln^2(1-x)-2R(x)+2\left(-1+\ln\frac{K_F^2}{\lambda}\right)\ln(1-x)\\
\\ &&\displaystyle -\frac{2}{\lambda}\ln(1-\lambda
x)+\frac{1}{2\lambda^2}\ln(1-\lambda
\\ &&\displaystyle +\frac{1}{2\lambda^2}\ln(1-\lambda
x)+\frac{1-\lambda}{2\lambda}\frac{x}{1-\lambda x}\bigg]\delta(1-z)
\end{array}\,.
\end{equation}
Expand Down

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