[SCU][Docathon][Add API Legend No.39]add the picture of unique-consecutive #6967
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unique-consecutive-kineast
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感谢你贡献飞桨文档，文档预览构建中，Docs-New 跑完后即可预览，预览链接：http://preview-pr-6967.paddle-docs-preview.paddlepaddle.org.cn/documentation/docs/zh/api/index_cn.html |
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- sample1 的图例感觉反而弄复杂了更难理解了，比如 input_position 和 output_position 不知道用处在哪。尽量从开发者的角度来设计图例，尽量保持简洁明了
- sample2 的 axis 弄反了， aixs=0是行，axis=1是列
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| - **x** (Tensor) - 输入的 `Tensor` ，数据类型为： float32、float64、int32、int64。 | ||
| - **return_inverse** (bool ，可选 ) - 如果为 True ，则还返回输入 Tensor 的元素对应在连续不重复元素中的索引，该索引可用于重构输入 Tensor 。默认： False。 | ||
| - **return_counts** (bool ，可选 ) - 如果为 True ，则还返回每个连续不重复元素在输入 Tensor 中的个数。默认： False 。 | ||
| - **axis** (int ，可选 ) - 指定选取连续不重复元素的轴。默认值为 None ，将输入平铺为 1-D 的 Tensor 后再选取连续不重复元素。默认： None 。 | ||
| - **dtype** (np.dtype|str ，可选 ) - 用于设置 `inverse` 或者 `counts` 的类型，应该为 int32 或者 int64 。默认： int64 。 | ||
| - **name** (str ，可选 ) - 具体用法请参见 :ref:`api_guide_Name` ，一般无需设置，默认值为 None 。 |
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| 将 Tensor 中连续重复的元素进行去重，返回连续不重复的 Tensor 。 | ||
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| 上图展示了一个一维张量的去重过程 | ||
| 下图展示了一个 [3, 4] 的二维张量沿 axis = 0 展开后去重再进行二维折叠的过程 | ||
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| .. figure:: ../../images/api_legend/unique-consecutive.png | ||
| :width: 500 | ||
| :alt: 示例二图示 | ||
| :align: center |
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图例部分加在 参数 板块上面，即API介绍的那部分
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| 代码示例 | ||
| :::::::::::: | ||
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| COPY-FROM: paddle.unique_consecutive | ||
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These 2 samples are uploaded.