Correct "expected output" mistake

[Arkangus]

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[schalkneethling]

Thank you for your contribution @Arkangus

It seems you might have identified a larger problem with this example. I have made a suggestion on a change.

[schalkneethling]

@Arkangus This is actually a little trickier and perhaps we should rewrite the example a bit. The reverse function is actually destructive i.e. it changes in place so, effects the original array as well. So, the output that it shown, is what is printed but, might be unexpected.

I therefore propose we change the example to the following:

var array1 = ['one', 'two', 'three'];
console.log('array1: ', array1);
// expected output: Array ['one', 'two', 'three']

var reversed = array1.reverse(); 
console.log('reversed: ', reversed);
// expected output: Array ['three', 'two', 'one']

/* Because `reverse`'s changes are done in place it
   also changes the original array, as can be seen here */
console.log('array1: ', array1);
// expected output: Array ['three', 'two', 'one']

Thoughts @wbamberg ?

[Arkangus]

Thanks for pointing that out. I definitely should have checked the actual answer!

I agree with the change. I would just replace

/* Because 'reverse''s changes are done in place it also changes the original array, as can be seen here */

By

/* Careful: reverse is destructive. It changes the original array */

I think it's clearer.

[schalkneethling]

r+ Thanks @Arkangus